The Friedman Test Calculator helps you perform non-parametric analysis for comparing three or more matched or repeated measurements. It determines whether samples originate from the same distribution by analyzing the ranks of the data rather than the raw values. This makes it particularly useful when your data violates the assumptions of repeated measures ANOVA, such as normality or sphericity. Common applications include comparing multiple treatments across the same subjects, analyzing repeated measurements over time, or evaluating preferences across different conditions. for a quick example.
Important considerations before using Friedman Test:
- The test requires at least 2 blocks/subjects and at least 3 treatments/conditions.
- Data should be organized with subjects as blocks and treatments as conditions being compared.
- The dependent variable should be at least ordinal (can be ranked).
- Blocks should be independent of each other, but measurements within blocks are related.
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Friedman Test
Definition
Friedman Test is a non-parametric alternative to the one-way repeated measures ANOVA. It tests for differences between three or more matched or paired groups, without requiring normality in the data distribution. The test statistic is based on the ranks of the data values within each block.
Test Statistic
Where:
- = number of blocks (subjects)
- = number of treatments
- = total rank of treatment
- when or
- for better accuracy when and
Key Assumptions
Practical Example
Step 1: State the Data
Scores for three treatments across five subjects:
| Subject | Treatment A | Treatment B | Treatment C |
|---|---|---|---|
| 1 | 8 | 6 | 5 |
| 2 | 7 | 7 | 6 |
| 3 | 9 | 8 | 6 |
| 4 | 6 | 5 | 4 |
| 5 | 7 | 6 | 5 |
Step 2: State Hypotheses
- : No difference between treatments
- : At least two treatments differ
Step 3: Rank Within Blocks
| Subject | A | B | C |
|---|---|---|---|
| 1 | 3 | 2 | 1 |
| 2 | 2.5 | 2.5 | 1 |
| 3 | 3 | 2 | 1 |
| 4 | 3 | 2 | 1 |
| 5 | 3 | 2 | 1 |
| 14.5 | 10.5 | 5 |
Step 4: Calculate Test Statistic
1. Basic Friedman statistic with b = 5 subjects and k = 3 treatments:
2. Correction for ties:
In our data, we have one tie (7,7) in Subject 2's scores.
where for each group of tied ranks
One pair of ties gives
3. Adjusted test statistic:
Step 5: Draw Conclusion
Critical value for with at is . Since , we reject .
There is sufficient evidence to conclude that there are significant differences between at least two treatments.
With -value = , there is strong evidence to conclude that there are significant differences between at least two treatments.
Effect Size
Kendall's W
Kendall's coefficient of concordance () ranges from (no agreement) to (complete agreement):
For our example:
Interpretation guidelines:
- : Weak agreement
- : Moderate agreement
- : Strong agreement
Code Examples
library(tidyverse)
# Create the data frame
data <- tibble(
Subject = c(
"Subject 1", "Subject 1", "Subject 1",
"Subject 2", "Subject 2", "Subject 2",
"Subject 3", "Subject 3", "Subject 3",
"Subject 4", "Subject 4", "Subject 4",
"Subject 5", "Subject 5", "Subject 5"
),
Treatment = c(
"Treatment A", "Treatment B", "Treatment C",
"Treatment A", "Treatment B", "Treatment C",
"Treatment A", "Treatment B", "Treatment C",
"Treatment A", "Treatment B", "Treatment C",
"Treatment A", "Treatment B", "Treatment C"
),
Score = c(8, 6, 5, 7, 7, 6, 9, 8, 6, 6, 5, 4, 7, 6, 5)
)
# Perform Friedman test
friedman_result <- friedman.test(Score ~ Treatment | Subject, data = data)
print(friedman_result)import pandas as pd
from scipy.stats import friedmanchisquare
import numpy as np
# Create the data frame
data = pd.DataFrame({
'Subject': [
'Subject 1', 'Subject 1', 'Subject 1',
'Subject 2', 'Subject 2', 'Subject 2',
'Subject 3', 'Subject 3', 'Subject 3',
'Subject 4', 'Subject 4', 'Subject 4',
'Subject 5', 'Subject 5', 'Subject 5'
],
'Treatment': [
'Treatment A', 'Treatment B', 'Treatment C',
'Treatment A', 'Treatment B', 'Treatment C',
'Treatment A', 'Treatment B', 'Treatment C',
'Treatment A', 'Treatment B', 'Treatment C',
'Treatment A', 'Treatment B', 'Treatment C'
],
'Score': [8, 6, 5, 7, 7, 6, 9, 8, 6, 6, 5, 4, 7, 6, 5]
})
# Reshape data to wide format for Friedman test
# Each row represents a subject, each column a treatment
data_wide = data.pivot(index='Subject', columns='Treatment', values='Score')
# Perform Friedman test
statistic, p_value = friedmanchisquare(
data_wide['Treatment A'],
data_wide['Treatment B'],
data_wide['Treatment C']
)
print(f'Friedman chi-squared = {statistic:.4f}')
print(f'p-value = {p_value:.6f}')
# Calculate Kendall's W (effect size)
n = len(data_wide) # number of subjects
k = len(data_wide.columns) # number of treatments
kendalls_w = statistic / (n * (k - 1))
print(f"Kendall's W = {kendalls_w:.7f}")